In this blog post, we will be discussing how to draw the major organic product for the following reaction.
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In organic chemistry, there are certain rules that govern the way electrons move in a molecule. These rules allow chemists to predict the major organic product for a given reaction. The following is a guide on how to draw the major organic product for the following reaction.
The Major Product
In organic chemistry, there are certain rules that dictate the arrangement of atoms in space. These rules allow us to predict which molecule will be the major product of a reaction. In this guide, we will go over how to determine the major product for the following reaction:
The products of this reaction are determined by looking at the two main reactants, butane and bromine. Butane is a alkane with the general formula C4H10, and bromine is a halogen with the general formula Br2. Alkanes are non-polar molecules, meaning that they do not have any regions of high or low electron density. This makes them unreactive with other molecules. Halogens, on the other hand, are very reactive because they have an uneven distribution of electrons. Bromine will push electrons onto the butane molecule, causing it to become polar.
The product of this reaction will be a compound with the general formula C4H9Br. The “Major Product” is determined by looking at the atoms that make up the product and deciding which arrangement of atoms is most stable. In this case, the most stable arrangement of atoms is the one that minimizes the amount of time that Bromine spends in contact with Butane. This can be accomplished by arranging the atoms so that Bromine is on one side of the molecule and Butane is on the other side. This arrangement is called “trans.”
The Reaction: Hydroboration of an alkene followed by oxidation
In this reaction, we start with an alkene and add borane (BH3) to it. This is called hydroboration. Then we oxidize the borane using hydrogen peroxide (H2O2) to give us our final product.
Here’s the step-by-step process for drawing the major organic product for this reaction:
1. Start with the alkene. In this example, we’ll use ethene (CH2=CH2).
2. Add borane (BH3) to one side of the alkene double bond. The borane will add itself to the less substituted side of the double bond. In our example, that would be the left side.
3. Add hydrogen peroxide (H2O2) to the other side of the double bond. The hydrogen peroxide will oxidize the borane, forming a hydroxyl group (-OH).
4. The final product is the alcohol on the left side of the double bond, with the hydroxyl group (-OH) on the right side.
In order to determine the organic product of the following reaction, we must first identify the conditions. The conditions are:
Once we know the conditions, we can then identify the reactants and products. The reactants are:
and the products are:
The mechanisms for the following reaction have been drawn out for you. All you need to do is determine the major organic product of the reaction.
The first step in any mechanism is to draw out the Lewis Structure of all of the reactants. In this case, we have two reactants: ethene (C2H4) and chlorine (Cl2).
The next step is to determine which atom will be the more electronegative atom. In this case, chlorine is more electronegative than hydrogen, so we will start with chlorine as our electrophile.
Chlorine will attack ethene from the side, forming a chloroethane molecule and a chlorine radical:
In conclusion, the major organic product for the following reaction is 4-methylpent-1-ene.